1=-0.6x^2+3x+4

Solution for 1=-0.6x^2+3x+4 equation:

1=-0.6x^2+3x+4

We move all terms to the left:

1-(-0.6x^2+3x+4)=0

We get rid of parentheses

0.6x^2-3x-4+1=0

We add all the numbers together, and all the variables

0.6x^2-3x-3=0

a = 0.6; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·0.6·(-3)
Δ = 16.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{16.2}}{2*0.6}=\frac{3-\sqrt{16.2}}{1.2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{16.2}}{2*0.6}=\frac{3+\sqrt{16.2}}{1.2}
$